## Pow Writeup for POW 9 Gumballs

Sean Holley

Writeup

Answers: In the first problem the first gumball could be either of the two colors. The second gumball had a more likely chance of getting the other color. Because of probability, if the first one was white the second one will most likely be red. Then on the third because in a perfect situation this one should be white.

In the second problem it could take her up to 4 tries. I found this out using the same method I explained in the first one. She will cycle through the three colors until on the 4th one where she is almost guaranteed to get a repeat color

In the third problem when mr. strater has his triplets and they have the gumball machine with the three different colors. The most amount he should have to spend is 7 cents. I found this using the equation from the previous two. The equation i used was (x-1) #colors +1

Dave is walking down the street with his 17 kids. They go by a gumball machine with 5 different colors. Each kid wants the same color. All he has is one dollar in pennies. Will this be enough to get all the gumballs?

Answer: yes this will be enough to get the same color. It should take 81 cents to get the same color for each kid. Leaving him with to many gumballs than anyone should have to deal with.

Formula-(x-1) #colors+1

Generalizations: The max amount he should have to spend is always more than the amount of colors. This is due to probability saying that more than two is always going to take more than two tries

In general these two people have too many kids who make too many demands.

Writeup

Answers: In the first problem the first gumball could be either of the two colors. The second gumball had a more likely chance of getting the other color. Because of probability, if the first one was white the second one will most likely be red. Then on the third because in a perfect situation this one should be white.

In the second problem it could take her up to 4 tries. I found this out using the same method I explained in the first one. She will cycle through the three colors until on the 4th one where she is almost guaranteed to get a repeat color

In the third problem when mr. strater has his triplets and they have the gumball machine with the three different colors. The most amount he should have to spend is 7 cents. I found this using the equation from the previous two. The equation i used was (x-1) #colors +1

Dave is walking down the street with his 17 kids. They go by a gumball machine with 5 different colors. Each kid wants the same color. All he has is one dollar in pennies. Will this be enough to get all the gumballs?

Answer: yes this will be enough to get the same color. It should take 81 cents to get the same color for each kid. Leaving him with to many gumballs than anyone should have to deal with.

Formula-(x-1) #colors+1

Generalizations: The max amount he should have to spend is always more than the amount of colors. This is due to probability saying that more than two is always going to take more than two tries

In general these two people have too many kids who make too many demands.